Question
Use the rules for limits to evaluate the following.(a) $\lim _{x \rightarrow 0} \frac{x^{3}-1}{x^{2}+1}$(b) $\lim _{x \rightarrow 1} \frac{x-1}{x^{3}}-\frac{1}{-1}$(c) $\lim _{x \rightarrow 1} \cos \left(\frac{\pi x}{x+1}\right)$(d) $\lim _{x \rightarrow 0} x^{2} \cos \left(\frac{1}{x}\right)$
Step 1
Therefore, the limit is: $\lim _{x \rightarrow 0} \frac{x^{3}-1}{x^{2}+1} = \frac{-1}{1} = -1$ (b) $\lim _{x \rightarrow 1} \frac{x-1}{x^{3}}-\frac{1}{-1}$ As x approaches 1, the first term approaches $\frac{0}{1} = 0$. Show more…
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