Question
Use the specified substitution to find or evaluate the integral.$$\begin{array}{l} \int_{0}^{1} \frac{d x}{2 \sqrt{3-x} \sqrt{x+1}} \\ u=\sqrt{x+1} \end{array}$$
Step 1
Step 1: Given the substitution $u=\sqrt{x+1}$, we can differentiate both sides to get $du = \frac{1}{2\sqrt{x+1}}dx$. Show more…
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