00:01
For this problem, we need to use squeeze theorem to determine the limit of x times 1 minus cosine of 1 over x as x approaches 0.
00:11
We begin by setting g of x equal to x times 1 minus cosine of 1 over x.
00:20
And then from here we want to find functions f of x and h of x such that f of x is less than or equal to g of x, and h of x is greater than or equal to g of x.
00:33
To do this, we begin by the fact that cosine of 1 over x, this is greater than or equal to negative 1, but less than or equal to 1.
00:45
Now if we multiply this by negative 1, we have 1 greater than or equal to negative cosine of 1 over x, this is greater than or equal to negative 1.
00:59
And then if we add 1 in this inequality, we have 2, this is greater than or equal to 1 minus cosine of 1 over x, that's greater than or equal to 0.
01:15
Now this tells us that 1 minus cosine of 1 over x, the absolute value of this is less than or equal to 2.
01:26
And if we multiply this by an absolute value of x, both sides, we have the absolute value of x times 1 minus cosine of 1 over x...