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Use the standard entropy data in Appendix G to determine the change in entropy for each of the reactions listed in Exercise 16.34. All the processes occur at the standard conditions and $25^{\circ} \mathrm{C}$.

$\Delta S=2.9 \frac{J}{K \cdot m o l}$$\Delta S=24.8 \frac{J}{K \cdot m o l}$$\Delta S=-113.2 \frac{J}{K \cdot m d}$$\Delta S=-24.7 \frac{J}{K \cdot m o l}$$\Delta S=15.5 \frac{J}{K \cdot m o l}$$\Delta S=290.0 \frac{J}{K \cdot m o l}$

Chemistry 102

Chapter 16

Thermodynamics

Drexel University

University of Kentucky

Brown University

Lectures

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A liquid is a state of mat…

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Use the standard entropy d…

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Use the standard molar ent…

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Calculate the standard ent…

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the standard and drop the change Is the change off? Dropping off certain reaction it is calculated at room temperature on is denoted by Delta s equation to calculate the change is represented Over here it is represented US s off. Rodham's minus s off the active for option e There's the reaction between carbon and oxygen to form, see or do so The product is carbon dioxide by reactions are carbon on oxygen each off the reactant and product has one mole substituting in the values the standard and drop it Jane turns out to be to a point 86 jewels for Kelvin For option B. We have with the action between oxygen and nitrogen to form two moles off, substituting in the values way have standard and drop it change us 24 point in jewels for Kelvin for auctions. See, there's a reaction between copper and sell for giving us the broader. See, youto s substituting in the values we have and drop it. Change equals negative. 113.2 jewels for Kelvin For option B, we have reaction between gosh, um CEO on dhe. It's too giving us C E o x two each of the reactors and products are in quantity off one mole on our standard and drop the chains turned out to be negative. 24.7 jewels were killed for option E. We have reaction between Ireland and go carbon di carbon carbon oxide substituting in the the values we have standard and raw Pigeon's turned out to be 21 point right, Jules, for children for the last option option if the reaction between C A s so full with water giving us to product CSO full plus water Montague substituting in the be actin ce and we have to mortals off reactant over here, substituting in the reactor, uh, substituting in the values we have standard and drop me change equals 290 jewels were killed.

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