00:01
Now let's look at an example where we want to simplify an expression first, using our properties and rules of summation, and then after that, evaluate our summation for varying values of the tapout number.
00:18
So here it's a summation i equal 1 to n of 2i plus 1 over n square.
00:25
Now our index of summation is i, and the tap out value is n.
00:34
So when i look at this and i see that i've got my expression 2i plus 1 divided by n squared, well, my denominator of n squared is a constant with respect to the summation, whose index of summation is i.
00:51
So i can bring that common factor of my n squared being in the denominator, we can think of summation i equal 1 to n of 1 over n squared times this 2 i plus 1 and that 1 over n squared being a constant with respect to the index of summation being an i i can bring that out in front of the summation so that's 1 over n squared times a summation i equal 1 to n of that 2 i plus 1 now we also have the property that the summation of an addition or subtraction is term by term summation.
01:35
So my 1 over n squared, i'll keep out as a factor.
01:39
Put brackets to show then the summation i equal 1 to n of 2i, then plus the summation i equal 1 to n of 1.
01:54
In the bracket, the first term, i have 2 times i.
02:00
So that factor of 2 can be brought in front of, just that first summation.
02:07
So 1 over n squared, open my bracket, two times the summation i equal 1 to n of i, and then plus the summation i equal 1 to n of 1.
02:24
So the properties that we've used so far, summation i equal 1 to n of terms a sub i plus b sub i, we can do term my term summation...