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Problem

Use the Table of Integrals on Reference Pages 6-1…

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Problem 9 Medium Difficulty

Use the Table of Integrals on Reference Pages 6-10 to evaluate the integral.

$ \displaystyle \int \frac{\sqrt{9x^2 + 4}}{x^2}\ dx $


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Related Courses

Calculus 2 / BC

Calculus: Early Transcendentals

Chapter 7

Techniques of Integration

Section 6

Integration Using Tables and Computer Algebra Systems

Related Topics

Integration Techniques

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Top Calculus 2 / BC Educators
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01:53

Integration Techniques - Intro

In mathematics, integration is one of the two main operations in calculus, with its inverse, differentiation, being the other. Given a function of a real variable, an antiderivative, integral, or integrand is the function's derivative, with respect to the variable of interest. The integrals of a function are the components of its antiderivative. The definite integral of a function from a to b is the area of the region in the xy-plane that lies between the graph of the function and the x-axis, above the x-axis, or below the x-axis. The indefinite integral of a function is an antiderivative of the function, and can be used to find the original function when given the derivative. The definite integral of a function is a single-valued function on a given interval. It can be computed by evaluating the definite integral of a function at every x in the domain of the function, then adding the results together.

Video Thumbnail

27:53

Basic Techniques

In mathematics, a technique is a method or formula for solving a problem. Techniques are often used in mathematics, physics, economics, and computer science.

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Watch More Solved Questions in Chapter 7

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
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Problem 45
Problem 46

Video Transcript

Okay, This question wants us to integrate this function using a table. So if we look in the back of the book, we see that the closest thing to this expression is this formula. So what we need to dio is somehow get this integral to look like this one. So we want a use squared as our function inside the square root. So we want you squared to be equal to nine x squared. So this means that you is equal to three x, so d'you is equal to three d X or D X equals d'you divided by three and some additional things that may come in handy. This means the X squared equals you squared, divided by nine. Okay, so now we can start substituting. So we have are integral of the square root of Well, nine x squared is what we call the you squared plus four, which is two squared, all divided by excess squared, which we said was you squared divided by nine times our chain roll factor of 1/3 d u. And this simplifies to nine divided by three outside the integral, so three times the integral of the square root of you squared plus four over you squared, do you? So now we can directly apply our formula and get three times negative square root you squared plus four divided by you Plus Ln of you plus square root you squared plus a sward But in this case, we already know what a square it iss So let's just write it in to save us a step plus c All right, now let's back Substitute everything so we know that you squared is nine x squared and you is three x so you can see a cancellation is gonna happen here plus the natural log of three x again So we can already see that the three and the 1/3 cancel over there, which gives us a final answer of negative square root nine X squared plus four about my ex, plus the natural log of three x plus the square root of nine x squared plus four plus c. And that's our final answer. Oh, but we need a factor of three here, remember? From right here

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Top Calculus 2 / BC Educators
Anna Marie Vagnozzi

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University of Michigan - Ann Arbor

Samuel Hannah

University of Nottingham

Joseph Lentino

Boston College

Calculus 2 / BC Courses

Lectures

Video Thumbnail

01:53

Integration Techniques - Intro

In mathematics, integration is one of the two main operations in calculus, with its inverse, differentiation, being the other. Given a function of a real variable, an antiderivative, integral, or integrand is the function's derivative, with respect to the variable of interest. The integrals of a function are the components of its antiderivative. The definite integral of a function from a to b is the area of the region in the xy-plane that lies between the graph of the function and the x-axis, above the x-axis, or below the x-axis. The indefinite integral of a function is an antiderivative of the function, and can be used to find the original function when given the derivative. The definite integral of a function is a single-valued function on a given interval. It can be computed by evaluating the definite integral of a function at every x in the domain of the function, then adding the results together.

Video Thumbnail

27:53

Basic Techniques

In mathematics, a technique is a method or formula for solving a problem. Techniques are often used in mathematics, physics, economics, and computer science.

Join Course
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