00:01
Okay, we want to solve the indefinite integral that is of the function.
00:06
Inverse cosine of x the minus 2 over x cubed dx.
00:11
And to do this, we'll be using u substitution so that we can use this following, this following integral solution from our given integral table, which is entry 88 in the given textbook, or again, there are many integral table sheets online.
00:30
So by using use substitution, we will reduce the.
00:32
This integral such that we're only finding the integral of arc cosine of u, which is equal to u times arc cosine of u minus root 1 minus u squared plus c.
00:43
So let's begin with our u substitution and say that our u is just equal to our x to the minus 2.
00:54
Because this way we should be able to cancel out this x cubed such that we're only dealing with our cosine, which is the goal, because we want to use this integral.
01:04
Formula.
01:06
So if u is equal to x to the minus two, this means that d u is equal to negative two, because again we do the power rule here, minus two, then subtract one from the exponent.
01:19
So we get minus two times x to the minus three, dx.
01:26
So as we can see, we have an x to the minus three and a dx already in our original integral.
01:33
So this means we have to bring the minus two over to the d u side so we can make a proper substitution.
01:38
So this means we have a negative 1 1 half du equal to x minus 3 dx so i'll make the substitution we can write out what this looks like so this means our integral is now multiplied by a factor of minus 1 half such that we can then write that we have a cosine or inverse cosine of u and the x the 1 over x cubed and the dx gets subbed with our negative 1 half du so this just means we have du because we already have our factor of negative 1 half...