use-the-table-of-phase-change-data-on-page-507-to-sketch-a-heating-curve-for-mercury-2

Name: use the table of phase change data on page 507 to sketch a heating curve for mercury 2
Uploaded: 2020-10-18
Duration: 1 min 56 s
Channel: Numerade
Description: Use the table of phase-change data on page 507 to sketch a heating curve for mercury.

Question

Use the table of phase-change data on page 507 to sketch a heating curve for mercury.

David Collins · Accepted Answer

question Number three is a heating curve question where they ask you using data from the table on page five or seven to sketch the heating curve for mercury. To do that, the curve is going to have temperature on the Y axis in Celsius. And then he added, on the X axis. So first thing that we do is we warm the substance up. We warned the substance up to its melting point, so it&#x27;s a solid down here, the melting point of Mercury&#x27;s negative 39 degrees Celsius. Then, if the temperature stays flat as we add heat to it in order to convert it from a liquid, I&#x27;m very a solid into a liquid, and the heat required is 2.7 calories per gram. So it&#x27;s not much, so we don&#x27;t have to add much heat to convert it from a solid to a liquid. Then we&#x27;ll increase the temperature to 357 degrees Celsius, and then we need to add to go from a liquid to a gas 70 calories. So we&#x27;re looking at about 2.5 times I&#x27;m sorry 25 times mawr heat than to go from a liquid to a gas than it&#x27;s required to go from a solid to a liquid. So that&#x27;s why this line is much longer and the temperature which that occurs is the boiling point, which is 3 57 degrees Celsius.

Anna Miller · Answer

question in 93 you&#x27;re using this table here too closely. A phase of dry came from ammonia. I already did mean a rough sketch in. You want to include up her ex and my excess in clear points. But for the sake of this video is have a rough sketch. And so what we have is the triple play down here and that moves towards huh where it would be a salad. And then between the triple play and the next point, which is the pilot, quite. We have the normal freezing. Then boiling point moved up until it hits the critical point to this Linus space here his that, um, location, harmonious salad. The instance. This area here is that instance in which ammonia it&#x27;s a liquid. And finally, this instant, here is the moment in which money is a gas. So once ammonia moves to well point likely event, it is a cast, and then a headset screwed quite appear, which is at 112 u tm. And 130.2 degrees Celsius. This here&#x27;s a T on this success in temperature, which is in Celsius down here in years

Ahmed Ali · Answer

everyone living continue first is a table and a full way. We make a relation between limb be and the warm over tea We&#x27;ve gone bad. The first limb B is three born 67 The 2nd 1 is 4.23 The 3rd 1 is 4.74 and perhaps one is 5.25 after that. 5.66 After that, things 0.7 So now we, uh, six phone you must count is them to confer? Then we can go now The one over tea which is two times symbol negatives to really 1.92 times pointing power Negative three. 1.85 times Pointing board negative three 178 times point Inborn Negative three and the 1.72 times Boyton Power Negative three and the loss of 0.1 point 67 Time, Tim, More negative three. So now we continue the people so we cannot draw. But he will need the people for graphs. But it must be like the full in BT, it would be curve like exists. And in case off Leiby with one over tea, it will be lying and like, sort of for there&#x27;s online like this. So these is answer all questions. 16 mine. Thank you.

David Collins · Answer

So for this one going toe sketchy heating curve for one mole of fuck came knowing that it as Theo the Delta H, uh, vaporization Delta H infusion and the solar heat capacities that are given from negative 57 degrees Celsius all the way up to 150 degrees Celsius. The key is to try to keep this as to scale is possible. So we&#x27;ll start out at negative 57 degrees Celsius and that native 57 degrees Celsius. We&#x27;re just above the melting point at negative 56.8. So what we have here is a liquid of octane as it is a liquid. We can then begin to heat up a liquid until it, uh, converts from the liquid phase into the gaseous phase well heated up. According to it, the Moeller heat capacity of liquid, which is 254.6 for the slope as we heat it up, will correspond to the 200 and 54.6, and we&#x27;ll continue to heat it up that particular slope until we reach the um, boiling point. Partain, which is 125.7 and then once we have reached the boiling point. We need to continue to add in some energy in order to get all of the liquid to become a gas. So this flow, then, is a function of the solar heat capacity of the liquid, which is 254 0.6 Jules per mole degree Celsius. Any amount of heat that we need to add will correspond to the length Uh, this line up here, which is a function of the Delta H vaporization Delta H, uh, vaporization is 41.5 pretty 1.5 killer jewels her. So if we have a mole, we want to make sure that on our scale down here, we have gone 41 point side Jules, and we&#x27;ll also want to make certain that this amount of he added from here to here corresponds to, because we have one mole 200 and 54 0.6 jewell. So obviously this line up here that needs to course 12 41.5 needs to be pretty long in order to keep it to scale. Needs to be good almost 200 times longer. I&#x27;m gonna run out of room then that&#x27;s all of the liquid Octane has been converted into gaseous octane. Then the temperature can continue to increase, and this slow will correspond to its more heat capacity of the gas 316 point. So we need to go 316.9 is greater than the 254.6. So that means the slope is going to be a little bit less Because more heat is required for an increase in temperature, I will continue to increase the temperature until we reach 50 degrees. Can slow will correspond to the three 16.9 killed. Jules No. All right, Jules, Per mold degree Celsius. And the slow is due to the amount of energy that we added energy that we add in order to go, uh, her degree Celsius, which in this case is going to be, are doing about when he 0.3 degrees from here to here. And because it requires 3 16.9 June, we have one mole per degree Celsius. This difference should be 24.3 multiplied by 3 16.9 or 7701 Jules of energy to go from this point to this point

Carli Tucci · Answer

Okay, so too draw our hitting her for our water sample that we&#x27;re heating from night of 20 degrees Celsius up to 120 today Celsius were first gonna want to draw out our template. So that&#x27;s gonna be our axes are X axis will represent our heat at it now why access will represent our temperature in degrees Celsius. Okay, Before we start, we need to recognize two key points that are gonna happen along our heating curve that we&#x27;re gonna need to Mark and those were gonna be our face changes. Our first phase change is gonna create occur at zero degrees Celsius, and this will be our melting of our solid water or ice into our liquid water. Her second phase change is gonna occur at 100 degrees Celsius and that&#x27;s gonna be our boiling when we&#x27;re changing our liquid water into gas or steam. And we it&#x27;s important to remember that on a heating curve or phase changes are gonna be represented by horizontal lines because we&#x27;re showing that all the energy were adding in is going to going into changing the inter molecular bonds that are formed between the molecules, whereas the deac diagonal portions overheating curve are going to represent simply raising the temperature of our water sample. Okay, so to get started, we&#x27;re gonna begin at negative 20 degrees Celsius. Make our way up to zero degrees Celsius for our first face change. Okay, now we&#x27;re at zero degree Celsius. We need to have a horizontal line. Just gonna represent our melting point. We&#x27;re melting just like that. Okay, so now before we can get all the way up to 120 degrees Celsius, we need to get to 100 degrees Celsius. Because if you remember, we need to get to our boiling a boiling point, which will be 100 degrees Celsius. So we&#x27;re gonna go from zero up to 100 degrees Celsius. Okay, Now, 100 degrees Celsius. We&#x27;re gonna have a similar portion. It&#x27;s gonna be a horizontal line again. And as we mentioned before, this is representing our boiling. And we&#x27;re gonna make this longer than our one eyed zero degrees Celsius because it takes more energy to make the phase change from liquid water into gaseous water than it does to make the face change from solid water into liquid water. Right to our last step. We&#x27;re heating her is gonna be going from 100 degrees Celsius up to 120 degrees Celsius. And there&#x27;s our endpoint just like that. All right, so before we&#x27;re done, we need Teoh. Mark the points of our heating curve. Where are melting and are boiling occur. So are melting. I&#x27;m gonna represent as M. And that occurs at zero degrees Celsius at this horizontal portion. Oops. Me! All right. So m that&#x27;s gonna root. Is that our melting? All right. Now we need to also represent our boiling points and as we already stated, or boiling of our water sample is gonna occur at 100 degrees Celsius. So at this other horizontal portion, I&#x27;m gonna represent that with a B. So there we go. We have our heating her for water. We represented our melting point here at zero degrees Celsius with an M and are boiling about 100 degrees Celsius for the B

Shazia Naz · Answer

solution for the problem. Using the density, uh, hydrating into each four 8 25 degrees Celsius. The number of malls more self by dressing. Yeah, can be mhm calculated. So most of hydrating, yeah, is equal to volume into density. Mhm is equal to by putting values behave. 25 mhm m l into 1.0 63 graham. But Molly later is equal to 25.9 dramas like prison. So calculated myself at raising his 25.9 grand and to h four. Mm. Now we find the number of moles of high treason. Number of months off into H four is equal to 25.9 Drum into its food into one mall, One more of a fight Raising divided by 32 0.4 52 Grandma fight crazy is equal to is 0.7 830 more. The energy needed to race the temperature form 25.0 degree Celsius two 113.5 decreasing Says can be calculated using Yeah. Mm hmm. Mhm. Using the formula Mm. He transferred is equal to in see mhm Delta T where Delta T is equal to 113.5 degrees senses minus 25. The three, since yes, is equal to 88.5 degree sense. Yes, yeah, and he transferred is equal to 0.78 30 more into 98.84. Joel, divided by one more into each four Yes, into 88.5 degree Celsius is equal to 68. 48 point seven of six point 85 Joel no to calculate for the energy needed it 113.5 degree Celsius. Use the equation below, so the vision is mhm. He transferred is equal to mm. Heat of vaporization is equal to number of moles of fight raising into Delta. Each vaporization is equal to 0.7830 mall into 43.0 Kino Joel, divided by one more high treason is equal to 33 point 7 kg. Joan. Yeah, so the overall heat required is our own heat required is equal to he transferred. Plus heat of vaporization is equal to six point 85 Joel less 33.7 kg Joel he is equal to the overall heat. Required is 40 point five. Hello, George. So the calculated amount of feet required is 40.5 kg. Jones

Problem

A jeweler pours liquid gold into a mold to make a…

Problem 3 Easy Difficulty

Use the table of phase-change data on page 507 to sketch a heating curve for mercury.

Answer

graph can't coppy
$357^{\circ} \mathrm{C}$
$-39^{\circ} \mathrm{C}$

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Liquids - Intro

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graph can't coppy$357^{\circ} \mathrm{C}$$-39^{\circ} \mathrm{C}$

Living by Chemistry

Lizabeth T.

Nadia L.

Morgan S.

Jacquelin H.

Liquids - Intro

Comparison Of Gases Liquids And Solids

Angelica M. StacyLiving by Chemistry

Lizabeth T.

Nadia L.

Morgan S.

Jacquelin H.

graph can't coppy
$357^{\circ} \mathrm{C}$
$-39^{\circ} \mathrm{C}$

Angelica M. Stacy

Living by Chemistry