00:01
So this problem, we have to approve that will facilitate the conversion of the f2x from f3 but not the conversion of lf2x from f2x.
00:19
So the first thing we do is we write down the reduction potential for both these and half reactions.
00:27
And since eclah is to be encampureness in animal, we can put the values of the value of the the capital for reaction one and reaction two.
00:42
It's just to find out the potential of the aneur, this will give us a direction towards the kind of value that they're looking for.
00:55
Now, if this first reaction has to occur, then eann has to be positive.
01:03
So the value of the potential has to be lessens 0 .17 and if the second reaction is not allowed to occur then e anil has to be greater than minus 0 .44 because the e -serm overall has to be negative.
01:27
One of the hapsor reactions that fits the bill here is the cadmium and the e -anol in this case is minus d of so if we look at the first reaction here, we can multiply 2 .77 by 2 because in this case, stagnum has two electrons and it doesn't affect our problem because a value that is less than 0 .77 will also be less than twice 0 .7.
02:11
And then you can't create e -cell, it's positive.
02:16
So the reaction content will keep us, yes, it will just be.
02:19
While when you put the same value, in the second case, the e -cell comes back to be negative, which means that reaction will not occur or not responding...