Question
Use the theorem to sketch a graph of the parabola given by the equation $(x-3)^{2}=2(y+1)$.
Step 1
The equation is given in the form $(x-h)^2 = 4a(y-k)$, where (h,k) is the vertex of the parabola. In this case, we have $(x-3)^2 = 2(y+1)$. Comparing the two equations, we can see that the vertex is at the point (h,k) = (3,-1). Show more…
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