Question
Use the trigonometric substitution to write the algebraic expression as a trigonometric function of $\theta,$ where $\mathbf{0}<\boldsymbol{\theta}<\pi / 2$$$\sqrt{25-x^{2}}, \quad x=5 \sin \theta$$
Step 1
Step 1: We are given the expression $\sqrt{25-x^{2}}$ and we are told to substitute $x=5 \sin \theta$ into this expression. Show more…
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