The vertex of a parabola given by the equation $f(x)=ax^2+bx+c$ is given by the point $(-\frac{b}{2a}, f(-\frac{b}{2a}))$. In this case, $a=-1$ and $b=2$, so the vertex is at $(1, f(1))$. Substituting $x=1$ into the equation gives $f(1)=2(1)-(1)^2-2=-1$. So the
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