The numerator $x^{2}-7x+10$ can be factored as $(x-2)(x-5)$ and the denominator $x^{6}-64$ can be factored as $(x^{3}+8)(x^{3}-8)$, which can be further factored as $(x^{3}+8)(x-2)(x^{2}+2x+4)$.
So, the expression becomes:
$$
\frac{x^{2}-7x+10}{x^{6}-64} =
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