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Use this information: At a time $t$ seconds after an object is tossed vertically upward, it reaches a height s in feet given by the equation $s=80 t-16 t^{2}$.What is the maximum height reached by the object?
Step 1
Step 1: The equation given is in the form of a quadratic equation, $s = at^2 + bt + c$, where $a = -16$, $b = 80$, and $c = 0$. Show more…
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Use this information: At a time $t$ seconds after an object is tossed vertically upward, it reaches a height s in feet given by the equation $s=80 t-16 t^{2}$. In how many seconds does the object reach its maximum height?
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An object is tossed vertically upward from ground level. Its height $s(t),$ in feet, at time $t$ seconds is given by the position function $s(t)=-16 t^{2}+80 t$. In how many seconds does the object reach its maximum height?
Use this information: At a time $t$ seconds after an object is tossed vertically upward, it reaches a height s in feet given by the equation $s=80 t-16 t^{2}$. In how many seconds does the object return to the point from which it was thrown?
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