00:01
So in this problem, we're given a situation like this.
00:03
We have a right triangle, and we're told the side links.
00:07
And so let me go ahead and fill those in.
00:10
Little r here is 3 root 2.
00:13
Little q is 2 root 3.
00:18
And this little p here is the square root of 6.
00:23
And so now the first thing we need to find is the sign of.
00:28
And so p is down here, and sign is opposite over hypotenuse.
00:32
So this is just going to be the square root of 6 over 3, square root of 2.
00:39
And we can actually cancel some of this.
00:42
So square root of 6 and square root of 2 is going to combine to just give the square root of 3 up top.
00:48
But 3 is going to remain down low.
00:51
And now let's plug this into the calculator, and i get 0 .58th.
01:00
And i'm only going to 2 decimal places because the problem says to the nearest hundreds.
01:06
And so we have sine up p.
01:07
Let's get cosine of p.
01:10
Cosine is adjacent over hypotenuse.
01:13
So the adjacent is 2 root 3 over 3 root 2.
01:21
And let's see, there's not much simplification that can happen here.
01:25
And so let's just plug this into the calculator...