00:01
So the question states that a spaceship fires its thrusters in an x and y direction.
00:07
And in the x direction, it accelerates at 5 .1 meters per second squared.
00:13
And in the y direction, it accelerates at 7 .3 meters per second squared.
00:17
And we're given the final velocity in the x direction is 3 ,775 meters per second.
00:24
And in the y direction, it's 4 ,816 meters per second.
00:28
And our task is to find what the magnitude and the direction of the velocity vector is of the spaceship when it first starts to accelerate.
00:42
So to do this, we can use our kinematic equation, which states that the final velocity is equal to the initial velocity plus the acceleration times the time.
00:54
So in the x direction, we have the final velocity as 3 ,775 meters per second is equal to the initial velocity, which we're trying to find, plus the acceleration, which is 5 .1 meters per second squared, times the time, which we are also given in the problem, which is 565 seconds.
01:29
So when we plug this in and we solve for v0, we find that in the x direction, the initial velocity is equal to 893 .5 meters per second...