00:01
In this problem, we're given a very long prompt.
00:03
Using a procedure similar to competitive hunter model show that each trajectory is traversed in a counterclockwise direction as time the key is increased.
00:14
Along each trajectory, both the rabbit and fox populations fluctuate between their maximum and minimum values.
00:22
The maximum and minimum values for the rabbit population occur where the trajectory intersects the horizontal line, y equals a over b.
00:30
For the fox population, they occur where the trajectory intersects the vertical line, x equals c over d.
00:37
When the rabbit population is at its maximum, the fox population is below its maximum value.
00:43
As the rabbit population declines from this point in time, we move counterclockwise around the trajectory, and the fox population grows until it reaches its maximum value.
00:56
At this point, the rabbit population is declined to x equal c over d.
01:00
And is no longer at its peak value.
01:02
We see that the fox population reaches its maximum value at a later time, than the rabbits.
01:09
The predator population legs behind the prey and achieving maximum values.
01:13
This effect is shown right here, where red is the rabbits, and you can see that the fox population legs behind.
01:26
Okay, they go in the positive direction, and we've got in the figure lines a over b.
01:40
I've got to get to my problem again here.
01:49
Okay, x and y.
01:58
Okay.
02:08
So y equals a over b.
02:15
X equals c over d.
02:19
And we've got the minimum values.
02:21
Okay.
02:25
Both populations from the graph, periodic functions of time so that population of foxes at time equals zero is minimum.
03:08
So y -o equals, or is less than a over b, and x -o is equal to c over d.
03:28
And i'm going to put a couple lines in here.
03:40
Okay, it's possible to notice that moments after t is equal to t -0, both populations grow.
04:22
That's very apparent in the graph.
04:29
So d x over d t is greater than zero and d y over d t is greater than zero.
04:40
So the trajectory passes to region two.
05:00
And then after t, the rabbit population reaches after t equals the lag time.
05:18
Rabbit population reaches max okay it reaches the max and that time at that time when the rabbit population is max box population is y equals a over b okay and we'll label that why um why max no that'll be x max a over b and afterwards the rabbit population increases the rabbit population decreases d x over dt less than zero while the fox population continues to grow.
07:06
Okay.
07:12
And it grows at d, y, or dt is greater than zero.
07:19
So then the curve passes to region three.
07:27
And then fox population max, it matches y max.
07:38
And then the rabbit population at this point.
07:40
Point is x equals c over d.
07:50
Then right after the fox population increases, and right after that, fox population decreases, d .y over dt is less than zero...