00:01
We're going to be finding the magnetic field of a wire at a position are less than the radius of the wire.
00:12
So we're given the current density inside the wire and to recognize that current density is equal to the current per unit area that is perpendicular to the current flow.
00:31
So here we have a variable current density.
00:35
It is the dentist in the center of the wire where the radius is zero, and it just linearly goes down from that point onwards.
00:46
But anyway, the way to approach us is to use amper's law, which says that if you have a loop, a path that goes all the way around in a circuit, that the magnetic field projected along to that path is equal to mu not times the current enclosed by that path.
01:12
And because of the cylindrical symmetry, the path that we want to draw is a circular path inside the wire, because we want to find the magnetic field inside the wire.
01:27
And so what we'll have to find is the current enclosed by that loop.
01:34
Which is going to be proportional to the integral of the current density times the area of that loop.
01:46
So it's kind of counterintuitive, but we actually don't have to do any integration on the left -hand side.
01:54
We're assuming that b is constant along that circular path, and going all the way around, it has a length of 2 pi r, where that little r, let me see if i can draw that in red or something, is the radius out from the center to the imaginary loop.
02:17
So the wire has a real radius that ends the wire, but here we're going out to the loop because we want to find the magnetic field at an arbitrary point inside.
02:31
For the current enclosed, we are going to have to take our current density and multiply it by the area of that blue area.
02:49
So it's a circle, and we can write down the area is rdr times 2 pi, 2 pi rdr.
03:02
So we're kind of making rings inside of that blue area, rings that have a circumference of 2xr, and i really should call it r -prime, and they have width dr prime, and we are going to integrate from 0 to r.
03:31
And that should get everything inside that blue area.
03:34
So yeah, it's kind of counterintuitive that the integral usually winds up on the right -hand side of ampeer's law...