Question
Using an allowable shearing stress of 58 MPa, design a solid steel shaft to transmit $18 \mathrm{kW}$ at a frequency of $(a) 30 \mathrm{Hz},(b) 60 \mathrm{Hz}$.
Step 1
We know that Power (P) = Torque (T) × Angular Velocity (ω) So, Torque (T) = Power (P) / Angular Velocity (ω) First, we need to find the angular velocity for each frequency. Angular Velocity (ω) = 2 × π × Frequency (f) (a) For 30 Hz frequency: ω = 2 × π × 30 = Show more…
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