00:04
Suppose we want to produce these molecules from alkenes.
00:11
How would we go about doing that? well, if we were to choose any alkyne and any reaction, well, this is the first example is just a cyclohegene.
00:21
So we can say that, well, we started with a cyclohexene and we reacted with hydrogen over palladium.
00:29
And there we have our product.
00:31
So let's just make this really simple and really easy.
00:33
Here, we're reacting or we're creating a cl substituent.
00:40
Now, we're going to just assume that that's kind of where the alkyan was, right? and what we can just say is, oh, we can react hcl, and our alkyne is going to be this one.
00:54
We could have it be there, but the cl could be in the middle or on that carbon.
01:00
So we're going to kind of eliminate that kind of uncertainty by having a terminal outking.
01:08
Because there is a very clear distinction between a more stable carbon and a less stable carbon.
01:15
So the hydrogen will most definitely take that carbon and the cl can go right here.
01:23
For this one, we want to add an alcohol group.
01:27
So what we can do is, well, it's going to be a.
01:32
It's an unstable alcohol or relatively unstable alcohol and what i mean by this is it's on the least stable carbon which is a terminal carbon it's the only primary carbon in the whole molecule so we can say is well we started with this alken right here and we just used hydroporation and that will produce our antimarkopnikov alcohol in our with our product here we are adding a bromine and an alcohol so we can say that this was bromine in the presence of water and we can say that the double bond was in between the two carbons that is involved here.
02:27
Here we're adding an alcohol so what we can do is well we can use this and say that we had a terminal alkyne and we just reacted it with h2o and h2s04.
02:50
This carbon and this carbon are both secondary carbons, and therefore they would make secondary carbonyms with this reaction...