00:01
Okay, so we have the following equation right here, n2 gas plus o2 gas yields 2 and o gas.
00:12
So they want us to determine the delta h, the delta s, and the delta g.
00:17
So in order to calculate all three of these, all you need to do is take the, so let's just do delta h first, actually.
00:24
So the delta h of the reaction is equal to the sum of the delta h on the product side.
00:34
Minus the sum of the delta h on the reactant side.
00:41
So let's start with the product side.
00:45
So delta h of the reaction, we have two moles of no, and the delta h of no is 90 kilo per mole.
00:55
Now minus, so we have one mole of n2 and the delta h is 0, plus one mole of oxygen and the delta h is 0.
01:05
So we don't even need to plug this in the calculator because 2 times 90 ,000.
01:08
Is 180 and 180 minus 0 is 0 so it's 180 kilojoules now for the next part we have delta s so delta s is the same thing is pretty much the sum of the delta s on the product side minus the sum of the delta s on the reacting side so let's start with the product side so we have two moles of n o the delta s of n o is 2 11 jou so minus 1 mole of n2 delta s is 192 plus one mole of 02, delta s is 205.
01:51
Right, we plug this in the calculator and we should get 25 joules.
01:57
Now for the delta g, delta g is also the same thing as the sum of delta g on the product side minus the sum of delta g on the reacting side...