00:01
All right, so we're looking now at problem 94 in chapter 22.
00:04
And what we're asked to do is go to appendix c, and then we want to calculate the equilibrium constant for equation 22 .22 at 298 kelvin standard temperature.
00:20
So first, let's write out equation 22 .22.
00:27
We have 302.
00:31
We're assuming no electrical input, but i'm going to write the equation as it's written.
00:40
Goes to 203, and then we're given the enthalpy of this.
00:57
Okay, so if we go to appendix c, the delta g of formation for ozone, is 163 .4 kilojoules per mole.
01:24
Now, in this reaction, we're forming two moles, so we're going to have to multiply this by two, but we'll be doing that later.
01:37
So we've got our free energy change, and now we need a relationship between the free energy change and the equilibrium constant, and the one that we'll use for that is that delta g standard equals negative rt, ln of k -e -q.
01:54
And we'll just rearrange this guy.
01:57
We'll multiply these two terms, the ideal gas constant, the temperature over, and then we'll take the exponent of both sides.
02:05
So finally, we arrive at negative e to the negative delta -g standard over r -t is equal to...
