Question
Using electrode potentials, calculate the standard free-energy change for the reaction$$\mathrm{Na}(s)+\frac{1}{2} \mathrm{Br}_{2}(g) \stackrel{\mathrm{H}_{2} \mathrm{O}}{\longrightarrow} \mathrm{Na}^{+}(a q)+\mathrm{Br}^{-}(a q)$$
Step 1
The oxidation reaction is when sodium loses an electron to form sodium ion: $$\mathrm{Na}(s) \rightarrow \mathrm{Na}^{+}(a q)+e^{-}$$ The reduction reaction is when bromine gains an electron to form bromide ion: $$\frac{1}{2} \mathrm{Br}_{2}(g) + e^{-} \rightarrow Show more…
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Using electrode potentials, calculate the standard freeenergy change for the reaction $$ \mathrm{Na}(s)+\frac{1}{2} \mathrm{Br}_{2}(g) \stackrel{\mathrm{H}_{2} \mathrm{O}}{\longrightarrow} \mathrm{Na}^{+}(a q)+\mathrm{Br}^{-}(a q) $$
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