Using elementary transformations, find the inverse of each of the matrices, if it exists.
$$
\left[\begin{array}{rrr}
1 & 3 & -2 \\
-3 & 0 & -5 \\
2 & 5 & 0
\end{array}\right]
$$

Answer

Related Courses

Algebra

NCERT Class 12 Part 1 - Math

Chapter 3

Matrices

Section 4

Operations on Matrices

Discussion

You must be signed in to discuss.

Top Algebra Educators

Watch More Solved Questions in Chapter 3

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Video Transcript

in the question. We have produced the elementary transformation and find the inverse for each of them metrics here. The matrix governess. The matrix with the element 13 minus two -30 -5, 250. Now moving towards the solution lack these metrics were represented by so A will be the metrics with the element 13 minus two minus 30 minus 5 to 5 zero. Now, as we know that we can represent this a metrics as a is calls for the identity matrix into way. So this will be written as the metrics 13 -2 -30 -5. 250 is equal to the identity matrix which is 100010001 into A. So now apply first to try so far 12 R two. That is your art will become our two plus try self are one now subtract twice so far one from our three. So are three will become our three minus twice of our one and now interchange your are too with our three. So doing these three steps, you will get your metrics as 1 3 -2 0 -1. -11 equals two. 100 -201 310 and two. Now apply multiply your R two by minus one. So too will become minus one and two are to, this will give you 1 3 -2 01 -409 -11. He's the coolest too. 100 20-1 three, and 28. Now apply subtract your to try so far too from Armand. So are one will become our one minus tries off to subtract nine times of our two from our three. So are three will become our three minus nine times of our two and now multiply our three by one by 25. So doing three steps, you will get 10 10 01 minus 4001 is supposed to -503, 20-1 -3 x 51 x 259 by 25- eight. Now moving further now apply uh subject 10 times of our three from are and so are one will become our one minus 10 times of our three and add four times of R three to R two. So are you will become our two plus four times so far to this will give you you're my princess 1000 10001 is equal to 1 -2 x 5 -3 x 5 -2, x five, x, 25, x 25 minus three by 51 by 25 9 by 25. And to a so from here you're a inverse will become one minus two by five minus three by five minus two by five, four x 25, x 25 -3, x five, x, 25, x 25. Thank you.

We have video lessons for 90.65% of the questions in this textbook