Question
Using Gauss's law, calculate the field intensity due a cylindrically symmetric charge distribution of uniform density of infinite length when the point lies inside the charge distribution.
Step 1
We need to calculate the electric field intensity due to a cylindrically symmetric charge distribution of uniform density (\(\rho\)) and infinite length. The point where we want to calculate the field is inside the charge distribution. Show more…
Show all steps
Your feedback will help us improve your experience
James Kiss and 67 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Use Gauss' Law $\nabla \cdot \mathbf{E}=\frac{\rho}{\epsilon_{0}}$ for an electric field E, charge density $\rho$ and permittivity $\epsilon_{0}$. The integral form of Gauss' Law is $\iint_{S} \mathbf{E} \cdot \mathbf{n} d S=\frac{q}{\epsilon_{0}},$ where $\mathbf{E}$ is an electric field, $q$ is the total charge enclosed by $S$ and $\epsilon_{0}$ is the permittivity constant. Use equation (7.1) to derive the differential form of Gauss' Law: $\nabla \cdot \mathbf{E}=\frac{\rho}{\epsilon_{0}},$ where $\rho$ is the charge density.
Vector Calculus
The Divergence Theorem
A solid, nonconducting sphere of radius $a$ has total charge $Q$ and a uniform charge distribution. Using Gauss's Law, determine the electric field (as a vector) in the regions $r<a$ and $r>a$ in terms of $Q$.
Use Gauss's law to find the electric field inside a uniformly charged sphere (charge density $\rho$ ). Compare your answer to Prob. 2.8.
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD