00:01
Alright, so the first question is asking a making a table with, there's a change in depth from 0 feet to 60 feet, and we just have to find a pressure.
00:11
So the equation is p equals 14 .7 plus .45d, and while p stands for the pressure in pounds per inch square, the d sends for feet.
00:25
So what we're going to do is we're going to plug in zero first in d.
00:30
So pressure equals to 14 .7 plus 0 .45 times 0.
00:43
Then we're going to get 14 .7 plus 0 equals to 0.
00:50
And we're going to just say p1 for that one.
00:54
And pressure 2, i'm going to say 14 .7 plus 0 .4.
01:01
1 .45 times 10 because you have to realize that p and d, they are the variable.
01:13
So they're the one that changing it while the 14 .7 and .45 are the constants.
01:19
So they are the constant even though when the pressure and depth still changes.
01:25
And if you have more questions about those kind of concept, you can refer to page 160 on chapter 1, section 10, i can upload this screenshot for you right there.
01:42
So it says that whenever the k y equals kx and k is not zero, then we say that it's a direct variation.
01:51
So let's get going.
01:52
So p2 equals to 14 .7 plus 4 .5, and that will be equal to what? if you're pulling the calculator, you'll get 19 .2.
02:07
And p3, kip going on, 0 .45 times 20 this time, that will be 14 .7 plus 9, and that will be equal to 23 .7.
02:27
And pressure 4 equals to 14 .7 plus 0 .45 times 30.
02:36
That will be equal to 13 .5.
02:45
And if you're pulling the calculator, it will be 28 .2.
02:49
And you just keep going until we reach to 60.
02:54
So i'm going to not do the rest of them.
02:57
And you realize that there's a pattern starting to show up.
03:00
Oh, actually this is 14 .7...