00:01
For this problem, we're being asked to only use the periodic table to determine the expected ground state electron configuration for four different elements.
00:10
So the first of those elements is going to be the third element in group 5a.
00:19
So first thing we want to do is find 5a, which is right here.
00:24
And then we're going to go down to the third one.
00:27
So it's arsenic.
00:29
Arsenic.
00:30
Arsenic is right here.
00:31
Here and now we're going to figure out the ground state for that.
00:35
So for arsenic, oops, i'll switch to my pen, and set my highlighter.
00:41
Arsenic, we're going to look at the full, the nearest full valence, or noble gas before it.
00:50
That's going to be argon.
00:53
So we have argon.
00:54
And then we're going to take into consideration what comes after argon.
00:58
So we have a 4s, and that's going to be full.
01:05
And then that will be a 3d, and that can hold 10 valence.
01:11
And then we have a 4p, and we have 1, 2, 3 electrons there.
01:17
So that is the ground state configuration for arsenic.
01:22
The next one is for element 116.
01:26
And if we just look, we found element 116 is right here.
01:30
Livorium.
01:32
So that is going to be, we're going to look at the noble gas before it, which is rn.
01:43
And then it will be 7s2, 5f14, because we can't forget that the lanthanides fit in right here.
01:54
Then 6d10 and 7p, 1, 2, 7p, 4, 7p4.
02:03
So that is the ground state for 116.
02:09
Now this one's a little bit more complicated.
02:11
We want to do it for an element with three unpaired 5d electrons.
02:18
So remember that this is s, these are d, these are p, and these are f.
02:25
And we also want to remember that d is one behind s.
02:29
So if this is 4s here, then this is 3d...