Question
Using orbital diagrams, describe how sp $^{3}$ hybridization occurs in each atom: (a) carbon, (b) nitrogen, (c) oxygen. If these elements use $s p^{3}$ hybrid orbitals to form bonds, how many lone pairs of electrons would be found on each?
Step 1
Carbon has 4 valence electrons, 2 in the 2s orbital and 2 in the 2p orbital. Nitrogen has 5 valence electrons, 2 in the 2s orbital and 3 in the 2p orbital. Oxygen has 6 valence electrons, 2 in the 2s orbital and 4 in the 2p orbital. Show more…
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