Question
Using $\tau_{\text {all }}=70 \mathrm{MPa}$ and $G=27 \mathrm{GPa}$, determine for each of the aluminum bars shown the largest torque $\mathbf{T}$ that can be applied and the corresponding angle of twist at end $B$.
Step 1
For bar 1, the diameter is 50 mm, so the radius is 25 mm. The polar moment of inertia for a solid circular shaft is given by the formula J = (pi * r^4) / 2. So for bar 1, J = (pi * (25)^4) / 2 = 7.63 * 10^6 mm^4. For bar 2, the diameter is 40 mm, so the radius Show more…
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Using $\tau_{\text {all }}=70 \mathrm{MPa}$ and $G=27 \mathrm{GPa}$, determine for each of the aluminum bars shown the largest torque $\mathbf{T}$ that can be applied and the corresponding angle of twist at end $B$
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