00:02
We're asked to use generalized induction to show that if we're given your recursive definition of a sequence on z plus cross z plus, then we have that, in terms of the sequence, have a given discrete formula.
00:35
So we're told that the sequence amn is defined recursively by a11 equals 5, and amn is equal to am -n -1 -n plus 2 if n equals 1 and n is greater than 1, and am -n -minus -1 plus 2, if n is greater than 1, which is the other case.
01:30
We want to show that am -n is going to be equal to 2 times n plus n plus 1 for all pairs mn in z plus squared.
01:54
So to do this, let's start with the base case.
01:57
So again, we have that a11, we said, is equal to 5, which is the same as 2 times 2 plus 1, which is the same as 2 times 1 plus 1.
02:13
So this checks out...