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Using the Bohr model, determine the energy in joules of the photon produced when an electron in a ${L} {i}^{2+}$ ion moves from the orbit with n = 2 to the orbit with n = 1.
Energy produced $E=1.470 \cdot 10^{-17}$
Chemistry 101
Chapter 6
Electronic Structure and Periodic Properties of Elements
Electronic Structure
Periodic Table properties
Carleton College
University of Maryland - University College
University of Toronto
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problem. 27 from Chapter six is asking us to determine the energy of a photon produced when an electron from a lithium ion moves from one orbit next so to you to do to solve this question, we are going to use this equation here which relates the energy with the nuclear charge with the or changing orbital. Um, kay is a constant that is provided. So this change in orbital, you want to have a positive value because it's just a change in energy. Um, the answer is going to be a positive value. So it's best to have your smaller orbital here and your larger value of your orbital here so that you get a positive result. So, um, uh, as our ion is lithium, our nuclear charge is going to be three. And we're gonna use ah, one as our and one orbital, and we're gonna use to as our second and orbital. So once we go ahead and plug these values and this is what we get. So 2.179 times 10 to the minus 18. Jules is a value of this constant here, and we have three squared multiplied by ah one minus 1/4. So when you multiply this out, what you get is 1.471 times 10 to the minus 17 jewels. Because this constant isn't jewels are answers already in jewels, and we don't have to do any kind of conversion.
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