Question
Using the Clausius-Clapeyron equation, estimate the temperature at which water boils at the top of Mount Everest (altitude $8854 \mathrm{~m}$ ). (The air pressure is about $0.5 \mathrm{~atm}$ at a height of $18 \mathrm{~km}$.)
Step 1
The boiling point of water at sea level is $100 \mathrm{~^\circ C}$ or $373 \mathrm{~K}$. Show more…
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Estimate the boiling point of water in Leadville, Colorado, elevation $3170 \mathrm{m}$. To do this, use the barometric formula relating pressure and altitude: $P=P_{0} \times 10^{-M g h / 2.303 R T}$ (where $P=$ pressure in atm; $P_{0}=1$ atm; acceleration due to gravity, $g=9.81 \mathrm{m} \mathrm{s}^{-2} ; \quad$ molar $\quad$ mass $\quad$ of $\quad$ air, $M=0.02896 \mathrm{kg} \mathrm{mol}^{-1} ; \quad R=8.3145 \mathrm{Jmol}^{-1} \mathrm{K}^{-1} ;$ and T is the Kelvin temperature). Assume the air temperature is $10.0^{\circ} \mathrm{C}$ and that $\Delta_{\mathrm{vap}} H=41 \mathrm{kJ} \mathrm{mol}^{-1} \mathrm{H}_{2} \mathrm{O}$.
Estimate the boiling point of water in Leadville, Colorado, elevation 3170 m. To do this, use the barometric formula relating pressure and altitude: $P=P_{0} \times 10^{-\mathrm{Mgh} / 2.303 \mathrm{RT}} \quad(\text { where } P=\text { pressure } \mathrm{in}$ atm; $P_{0}=1 \mathrm{atm} ; g=$ acceleration due to gravity; molar mass of air, $M=0.02896 \mathrm{kg} \mathrm{mol}^{-1} ; \quad R=$ $8.3145 \mathrm{Jmol}^{-1} \mathrm{K}^{-1} ;$ and $T$ is the Kelvin temperature). Assume the air temperature is $10.0^{\circ} \mathrm{C}$ and that $\Delta H_{\text {vap }}=41 \mathrm{kJ} \mathrm{mol}^{-1} \mathrm{H}_{2} \mathrm{O}$
The barometric equation 1.46 and the Clausius Clapeyron equation 6.8 can be used to estimate the boiling point of a liquid at a higher altitude. Use these equations to derive a single equation to make this calculation. Use this equation to solve Problem 6.2.
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