00:01
Hey guys, so in this question, we're asked to find resonance structures for each of these compounds, given the curved arrows that were given in the textbook.
00:11
So in part a, we have this compound, and we have this curved arrow right here, denoting that electrons from this triple bond are moving to this nitrogen here.
00:23
So remember, when we have a curved arrow with two arrowheads right here, that means a pair of electrons are moving as opposed to one.
00:34
So when we redraw this structure, we have our ch3 remains the same.
00:39
Our c is going to be here.
00:41
And instead of three bonds, we are going to have a double bond here instead, since the electrons are now moving to the nitrogen.
00:50
So we'll have two pairs of electrons.
00:57
Now that we have this, we just need to make sure we have.
01:00
Our formal formal charges.
01:03
So we are going to have a negative charge on the nitrogen.
01:10
Since nitrogen has five valence electrons, we're going to subtract the number of bonds we have, so it's two, and we're also going to subtract the number of lone pairs of electrons we have, so we have four electrons.
01:25
So that's five minus six, so that's a negative one.
01:29
And then on this carbon, we have four valence electrons, and then we're going to subtract the number of bonds.
01:36
So that's three bonds.
01:38
So that's four minus three.
01:39
So that's a positive one.
01:43
So remember when we do resident structures, we want to make sure that the net charge of our formal charges is the same for both structures.
01:51
So when we add these together, we get a net of zero, which is the same as what we started with.
01:57
Moving on to part b, we have this compound right here.
02:01
So we see that the one pair of electrons is moving to this carbon or to this bond right here to fill the octet of the middle carbon right here...