00:01
So for the first part of this question, we're trying to calculate the mass of argon at a specific temperature, pressure, and volume.
00:07
So if we further calculate the volume, it's going to be 1000 meters cubed.
00:20
But if we want to put it into our ideal gas equation, which is pressure times volume equals n the moles times r the gas constant times t the temperature, we need to convert that meters cubed into liters.
00:36
And that's because r, our gas constant, is in the units liters times atmospheres over kelvin times moles.
00:45
So the gas constant tells us what each part of the equations units need to be.
00:51
So volume needs to be in liters, and one cubic meter is equal to 1000 liters.
01:01
So there's 1000 liters for every one cubic meter.
01:06
Cubic meters cancel out, and your answer is 1 times 10 to the 6th liters.
01:15
So now we have liters and atmospheres, but our temperature is in celsius and it needs to be in kelvin.
01:20
So to convert celsius into kelvin, we just add 273.
01:26
So our new temperature is going to be 298 kelvin.
01:29
So now we can plug these values into our ideal gas equation to solve for n the moles, which if we rearrange that to get n by itself, it's going to be pressure times volume divided by r the gas constant times t the temperature.
01:45
So it's going to be our pressure at 1 atmosphere times our volume, which is 1 times 10 to the 6th liters, divided by our gas constant, liters times atmospheres over kelvin times moles, times our temperature, which was 298 kelvin.
02:06
So our liters cancels out, our atmospheres cancel out, our kelvins cancel out, so we're left with moles.
02:13
So type this into your calculator, and you should get 4 .18 times 10 to the 4th moles.
02:27
So now we know how many moles of argon there are, but we want to know the mass of argon.
02:33
So when we convert moles into grams, we take it times its molar mass.
02:40
So we take it times the molar mass of argon, which is 39 .95 grams per mole.
02:51
Moles cancel out.
02:53
Type that into your calculator.
02:54
You should get 1 .67 times 10 to the 6th grams of argon...