09 x^{3} + 0.5 x^{2} - 0.1 x + 1 \). The first derivative, \( f'(x) \), will help us determine the critical points where the function may have relative maxima or minima.
\[
f'(x) = \frac{d}{dx}(-0.09 x^{3}) + \frac{d}{dx}(0.5 x^{2}) - \frac{d}{dx}(0.1 x) +
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