Question
Using the Heisenberg uncertainty principle, calculate $\Delta x$ for each of the following.a. an electron with $\Delta v=0.100 \mathrm{m} / \mathrm{s}$b. a bascball (mass $=145 \mathrm{g}$ ) with $\Delta v=0.100 \mathrm{m} / \mathrm{s}$ How does the answer in part a compare with the size of a hydrogen atom? How docs the answer in part b correspond to the size of a baseball?
Step 1
Mathematically, this is represented as $\Delta x \Delta p \geq \frac{h}{4\pi}$, where $\Delta x$ is the uncertainty in position, $\Delta p$ is the uncertainty in momentum, and $h$ is Planck's constant. Show more…
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Using the Heisenberg uncertainty principle, calculate $\Delta x$ for each of the following. a. an electron with $\Delta v=0.100 \mathrm{m} / \mathrm{s}$ b. a baseball (mass $=145 \mathrm{g}$ ) with $\Delta v=0.100 \mathrm{m} / \mathrm{s}$ How does the answer in part a compare with the size of a hydrogen atom? How does the answer in part b correspond to the size of a baseball?
Using the Heisenberg uncertainty principle, calculate $\Delta x$ for each of the following. a. an electron with $\Delta v=0.100 \mathrm{m} / \mathrm{s}$ b. a baseball (mass $=145 \mathrm{g} )$ with $\Delta v=0.100 \mathrm{m} / \mathrm{s}$ c. How does the answer in part a compare with the size of a hydrogen atom? d. How does the answer in part b correspond to the size of a baseball?
a. Use the Heisenberg uncertainty principle to calculate Δx for an electron with Δv = 0.370 m/s. b. By what factor is the uncertainty of the (above) electron's position larger than the diameter of the hydrogen atom? (Assume the diameter of the hydrogen atom is 1.00×10-8 cm.) c. Use the Heisenberg uncertainty principle to calculate Δx for a ball (mass = 192 g, diameter = 8.45 cm) with Δv = 0.370 m/s. d. The uncertainty of the (above) ball's position is equal to what factor times the diameter of the ball?
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