Using the last exercise as a guide, justify the following statement Let $\vec{v}_{1}, \vec{v}_{2}, \ldots, \vec{v}_{m}$ be vectors in $\mathbb{R}^{m}$ such that the $\mathrm{ma}$ trix
$$S=\left[\begin{array}{cccc}
| & | & & | \\
\vec{v}_{1} & \vec{v}_{2} & \dots & \vec{v}_{m} \\
| & | & & |
\end{array}\right]$$
is invertible. Let $\vec{w}_{1}, \vec{w}_{2}, \ldots, \vec{w}_{m}$ be arbitrary vectors in $\mathbb{R}^{n} .$ Then there exists a unique linear transformation $T$ from $\mathbb{R}^{m}$ to $\mathbb{R}^{n}$ such that $T\left(\vec{v}_{i}\right)=\vec{w}_{i},$ for all $i=1, \ldots, m,$ Find the matrix $A$ of this transformation
in terms of $S$ and
\[\boldsymbol{B}=\left[\begin{array}{cccc}
| & | & & | \\
\vec{w}_{1} & \vec{w}_{2} & \dots & \vec{w}_{m} \\
| & | & & |
\end{array}\right].\]