00:01
We're given a triangle, and we're asking us the law of cosines to solve this triangle, and to round our answer to two decimal places.
00:10
So we're given the side lengths of a triangle.
00:14
This is a side, side, side side triangle, where side a has length 75 .4, side b has length 52, and side c has length 52.
00:35
Now, to solve this triangle, we want to find the measures of angles a, b, and c.
00:39
So first i find a measure of angle a using the law of cosines.
00:47
So we have the cosine of a is equal to b squared plus c squared minus a squared over 2bc.
01:08
Plugging in this is 52 squared plus 52 squared minus 75 .4 squared over 2 times 2 .4 squared over 2 times 52 times 52.
01:25
This is approximately.
01:33
Negative 0 .051 -125.
02:11
Now, because this angle, cosine of this angle is negative, it follows that the measure of our angle a is going to be 180 degrees minus the inverse cosine about of negative.
02:28
0 .05125.
03:09
So plugging this in, this is approximately 87 .06 degrees.
03:28
Now to find the measure of angle b, we'll use law of signs, we know that the sign of b is equal to b times the sign of a over the length of a.
03:43
And this is approximately the length of side b, which is 52 times the sign of about 87 .06 degrees.
03:58
Over a, which was 75 .4...