Question
Using the Limit Comparison Test In Exercises $17-26,$ use the Limit Comparison Test to determine the convergence or divergence of the series.$$\sum_{n=1}^{\infty} \frac{2 n^{2}-1}{3 n^{5}+2 n+1}$$
Step 1
Step 1: First, we identify the series $\sum_{n=1}^{\infty} \frac{2 n^{2}-1}{3 n^{5}+2 n+1}$ and we can see that the terms $a_n = \frac{2 n^{2}-1}{3 n^{5}+2 n+1}$ and $b_n = \frac{1}{n^{3}}$. Show more…
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