00:01
So let's start with a free body diagram.
00:04
We have a force at a in the wide direction and force at b.
00:15
And then at c, we have 12 kips.
00:23
And then we have this.
00:31
And this is 2 .5.
00:39
And from here to here, 6 feet.
00:46
From here to here, 4 feet.
00:48
So i'm going to solve for a in the y direction, the a force.
00:58
So i'm going to do the moment at b, which is zero.
01:04
So negative ay times 10 plus 2 .5 times 6, 6 over 2 plus 4 plus 12 times 4.
01:19
And to get this, we're just doing, we're finding the force at the center.
01:26
So 2 .5 times 6, and then we take half the distance of 6 foot or 6 feet, and add the rest of your distance to b.
01:45
So solving for all that, we get ay is equal to 15 .3.
01:56
So now we can look at the shear forces on the beam, and our shear force at a is going to be the same as the value that we just calculated, it, a in the y direction.
02:06
So va is equal to 15 .3.
02:15
And then our shear force is going to be linear from point a to point c.
02:23
And at point c, we have 15 .3 minus 2 .5 times 6, which we get 0 .3...