00:02
So for this problem, we can start with a free -to -body diagram.
00:07
And we have a and c.
00:13
And at point b, we have a force p, l over 3, 2l over 3.
00:27
And i'm going to take the moment at c.
00:34
Also, let's call this r -a and r -c.
00:39
So our moment is going to be negative r a times l plus p times 2l over 3.
00:55
And solving for r a we get 2p over 3.
01:07
And at point a, also this is this is also v or share 4.
01:15
So our v is going to be constant till point b.
01:21
And at point b, we're going to have v.
01:32
2p over 3 minus p, which is equal to negative p over 3.
01:48
Then from b to c, it's constant.
01:52
And now i'm just going to do the bending moment at point a.
02:00
So we're going to have dm over d x equals v, which also is equal to 2p over 3.
02:14
So at point b we have mb equals 0 plus 2p over 3 times l over 3, which ends up equaling to 2...