00:01
So we're looking at a sphere, solid sphere, that has the charge queue evenly spread out throughout all of its volume.
00:10
And we want to know the electric field for when our variable r is outside of the sphere.
00:20
Electric field for when our variable r is inside of the sphere.
00:26
And then we want to sketch a little graph of that.
00:30
Outside of the sphere, because this is based off the assumption of another problem, or the results of another problem, where we say that once we're outside, because of gauss's law, we can just treat it as if it's all concentrated as a point charge at the center.
00:46
So this is going to look exactly like the electric field of a point charge, which is charge q, 4 pi r squared, and in the radial direction.
00:59
But we're looking for magnitude, so we're not even going to worry about direction.
01:05
And our q is q, so we're just leaving it.
01:07
This is the electric field outside that sphere.
01:11
It gets a little trickier inside the sphere.
01:15
Because if it's evenly distributed, as we're integrating from the center and our little gaussian sphere is getting larger and larger, we're enclosing more and more charge.
01:26
We haven't enclosed the total q yet.
01:29
So let's introduce a volume charge density, where this is the total charge q divided by the volume of the sphere.
01:39
And so our q enclosed as this gaussian sphere gets larger and larger is going to be this volume charge density times the differential volume we're enclosing.
01:52
So on our other side of gauss's law, we have this e .d .a.
01:56
This area is getting larger because we're getting a larger sphere.
01:59
But it's enclosing a larger volume as well.
02:03
So that's going to be four thirds pi variable r cubed.
02:10
This is all over epsilon not.
02:11
And this is equal to that integral, which that integral is going to give us the 4 pi variable r squared.
02:21
Okay, we can already cancel it out...