00:01
In this question, we are determining the structure of polyatomic ions by using vesper theory.
00:07
First, we are looking at the dihydrogen phosphate ion, and our first step is to be counting the number of available valence electrons.
00:16
So we have two hydrogens, each which have one valence electron, a phosphate with five valence electrons, four oxygens with six valence electrons each, and an overall charge of negative one indicates that we have one.
00:30
Extra electron because each electron has a charge of negative 1.
00:34
We add this together and we get 32.
00:37
Phosphate is our central atom.
00:39
We have four oxygens branching off.
00:43
We then attach our two hydrogens to our oxygens.
00:49
Now we count the number of electrons that have already been implemented.
00:54
So each of our bonds here has two electrons.
00:57
We have one, two, three, four, five, six bonds.
01:03
So that's 12 electrons, meaning we have 20 more to distribute.
01:08
So we start with our oxygens, 6, 12, 16, 20.
01:18
Our hydrogens won't get any electrons because they only have room for two valence electrons in their shells and their first valence shells and those have already been fulfilled with the bond.
01:29
Now we have four bonding pairs around our central atom of phosphate, and according to vesper, that is a tetrahedral.
01:43
Next, we are looking at the perchlorate ion.
01:45
Here we have seven valence electrons from chlorine, six valence electrons from our four oxygens, and an added charge of an added electron for the negative one charge.
01:57
This gets us to 32...