00:01
So if we want to show natural log of x squared plus y squared is harmonic, what we need to do is find the second partials with respect to x and y add it together and show this is going to be equal to zero.
00:15
So let's go ahead and find these partials.
00:17
So let's do with respect to x first.
00:21
So to take the derail of that, we'll just use chain rule.
00:24
So it'll be 1 over x squared plus y squared and then del by del x of x squared plus y squared.
00:32
And now remember we're going to assume y is a constant with respect to x.
00:36
So the derivative that is 0, the derivative this is 2x.
00:41
And so that would give us 2x over x squared plus y squared.
00:47
Now, if we want to take the derivative of this here, we're going to have a function that depends on x over a function that depends on x, which would mean we would want to use quotient rule.
00:59
So the second partial with respect to x is going to be.
01:03
So you have x squared plus y squared del by del x of 2x minus.
01:15
Then we switch them.
01:17
So 2x del by del x of x squared plus y squared all over what we have in the denominator squared.
01:30
So derivative of 2x is going to be not zero.
01:35
And then the derivative of x squared it's going to be 2x and then y squared well since y is a constant this is zero and now let's distribute the two and multiply those together so we get 2 x squared plus 2 y squared minus 4 x squared all over x squared plus y squared squared squared and now we can go ahead and combine those terms in the numerator so that gives us 2y squared minus 2 x squared all over x squared plus y squared squared squared squared.
02:19
All right, so now let's go ahead and find the second partial with respect to y...