Sign up for our free STEM online summer camps starting June 1st!View Summer Courses

University of New Mexico

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46
Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
Problem 56
Problem 57
Problem 58
Problem 59
Problem 60
Problem 61
Problem 62
Problem 63
Problem 64
Problem 65
Problem 66
Problem 67
Problem 68
Problem 69
Problem 70
Problem 71
Problem 72
Problem 73
Problem 74
Problem 75
Problem 76
Problem 77
Problem 78
Problem 79
Problem 80
Problem 81
Problem 82
Problem 83
Problem 84
Problem 85
Problem 86
Problem 87
Problem 88
Problem 89
Problem 90
Problem 91
Problem 92
Problem 93
Problem 94
Problem 95
Problem 96
Problem 97
Problem 98
Problem 99
Problem 100
Problem 101
Problem 102
Problem 103
Problem 104
Problem 105
Problem 106
Problem 107
Problem 108
Problem 109
Problem 110
Problem 111
Problem 112
Problem 113
Problem 114
Problem 115
Problem 116

Need more help? Fill out this quick form to get professional live tutoring.

Get live tutoring
Problem 95

Vanillin, the dominant flavoring in vanilla, contains $\mathrm{C}, \mathrm{H}$ , and $\mathrm{O} .$ When 1.05 $\mathrm{g}$ of this substance is completely combusted, 2.43 $\mathrm{g}$ of $\mathrm{CO}_{2}$ and 0.50 $\mathrm{g}$ of $\mathrm{H}_{2} \mathrm{O}$ are produced. What is the empirical formula of vanillin?

Answer

$C_{8} H_{8} O_{3}$

You must be logged in to like a video.

You must be logged in to bookmark a video.

## Discussion

## Video Transcript

let's start. Firstly, we need to calculate the mass off CEO and IT Adam in carbon dioxide and water, respectively. So the moss off carbon is 0.66 to 7 grams by the mass off hydrogen is 0.561 ground. To determine the mass off oxygen, we just simply data mine. We just simply subtract the mass off fire carbon on hydrogen from the total mouth off the sample, which gives us the mask off oxygen as 0.33 grounds. Now we need to calculate the moles off each element. The formula to data mine. The number off moves off each element. Is weight divided by the molecular mass. Using this formula, we can data mine the number off moves off carbon, hydrogen and oxygen. No to data mine. This impressed bull number ratio by dividing each mole by 0.7 mole because so for carbon it is 0.0 552 divided by 0.207 which gives US 2.66 for hydrogen, it is 0.554 divided by 0.0 207 gives us 2.67 For excision, it is 0.207 divided by 0.207 Gives us what the subscript off carbon and hydrogen are not. Wool number saw him, so we multiplied them by three to get the whole number. So multiplied them by three. Which gives us a goblin as eight Hydro Jinnah's eight excision as three. Which gives us the final empirical formula off the molecule compound. I see it. It's speed 43

## Recommended Questions