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Variation of the rate constant with temperature for the first-order reaction$$2 \mathrm{N}_{2} \mathrm{O}_{5}(g) \longrightarrow 2 \mathrm{N}_{2} \mathrm{O}_{4}(g)+\mathrm{O}_{2}(g)$$ is given in the following table. Determine graphically the activation energy for the reaction. $$\begin{array}{lc}\hline T(\mathbf{K}) & k\left(\mathbf{s}^{-1}\right) \\\hline 298 & 1.74 \times 10^{-5} \\308 & 6.61 \times 10^{-5} \\318 & 2.51 \times 10^{-4} \\328 & 7.59 \times 10^{-4} \\338 & 2.40 \times 10^{-3} \\\hline\end{array}$$

$$103 \mathrm{kJ} / \mathrm{mol}$$

Chemistry 102

Chapter 6

Chemical Kinetics

Kinetics

University of Central Florida

Rice University

University of Maryland - University College

University of Kentucky

Lectures

22:42

In probability theory, the conditional probability of an event A given that another event B has occurred is defined as the probability of A given B, written as P(A|B). It is a function of the probability of B, the probability of A given B, and the probability of B.

04:55

In chemistry, kinetics is the study of the rates of chemical reactions. The rate of a reaction is the change in concentration of a reactant over time. The rate of reaction is dependent on the concentration of the reactants, temperature, and the activation energy of the reaction.

01:44

The rate constant for the …

02:03

Calculate the activation e…

bolos Today we're going to be looking at a situation where we have a reaction and at ah, the temperature 298 Calvin. Our rate constant is 1.74 times 10 to the negative five inver seconds and that 308 Calvin it's 6.61 times 10 to the negative five inverse seconds. So we're going to try toe, figure out exactly what the activation energy is. So hopefully you should know if we graph one over tea and the natural log of K, our slope is going to be in the negative activation energy over our So let's take the scope. So in the numerator, we're going to have the natural log of K. So this point, the tea is greater and it's in the denominator. So that would be this point right here. And that's the point. That is the initial and this point is right here. So that's sort of our final. So we've got the natural log 1.74 times 10 the negative five subtracting the natural log of 6.61 times 10 to the negative five and now you're going tohave one over 298 Calvins attracting one over 308 Calvin. And so we'll going to do some maths and we will see Metro Log of 6.61 times 10 to the negative five is negative. 9.6 natural log of 1.74 times 10 to the five. Subtract not, and we're going to get negative. Ah, 12,000, 250 and this is going to equal negative activation energy over our, which is eight 0.314 So let's rearrange this and we will see that the activation energy is 100 and one 1008 150 jewels. So if we rearrange that, that would be 100 one 0.85 Kalid Jewell's

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