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The first step in this question is to identify what elements a, b, and c are.
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And if you compare the blank periodic table with one that is filled out, you will identify that a is lithium, b is gallium, and c is carbon.
00:23
So for part a, we are writing the formula of the oxide that has each of the elements in its highest oxidation state.
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And so we're going to essentially combine each of these elements with oxygen in a way that renders the oxidation states of each of the elements zero.
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So for example, with lithium, its oxidation number is plus one, and oxygen is minus two.
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So we're going to write that as la2.
00:53
For gallium, that is in group 3a.
00:59
So gallium is going to be and carbon is in group 4a so that is going to be written as co2 or carbon dioxide for part b we're determining which of those oxides is the most ionic and which is the most covalent and to solve that you look at the location on the periodic table the ionic compounds are predominantly made from metals on the left side of the periodic table so the most most ionic is going to be l .i .2 .o...