00:01
Welcome back for this problem.
00:03
We have two vectors.
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We'll close first vector vector a.
00:10
This little arrow above the a denotes that it's a vector.
00:15
It has both magnitude and a direction and vector b.
00:21
All right, and those are going to form a resultant vector of length 15 units.
00:32
We know that vector a is 12 .3 units.
00:39
All right, so there's our problem right there.
00:41
So we need to first find the length of or magnitude of vector b.
00:48
So using the pythagrin theorem, you can say that 15 squared is equal to b squared plus a squared, which is 12 .3 units.
00:59
You can subtract 12 .3 from both sides and then take the square root of both sides.
01:11
Square root, square root, and that will give us that b is equal to 8 .6 units.
01:22
And we need to also find the direction of the resultant vector.
01:29
So we're going to find this angle theta right here.
01:32
We can do that.
01:35
Theta is equal to the arc tangent of the side opposite of angle theta, which is side b, which we found earlier was 8 .6 units over 12 .3 units.
01:57
So theta is going to be equal to 34 .9 degrees.
02:05
All right, there's the first part of our, first excuse me, two parts of our problem...