Question
Velocity of a bullet changes from $u$ to $v$ after passing through a board of thickness $d$. Force of resistance is directly proportional to the velocity. Time of motion of bullet in the board is given by(a) $\frac{d(u-v)}{u v \log _{\ell} \frac{u}{v}}$(b) $\frac{d u}{v \log _e \frac{u}{v}}$(c) $\frac{d v}{u \log _e \frac{u}{v}}$(d) $\frac{d(v-u)}{u v \log _{\ell} \frac{v}{u}}$
Step 1
Since the force of resistance is directly proportional to the velocity, we can express this as \( F = -k v \), where \( k \) is a constant of proportionality and the negative sign indicates that the force opposes the motion. Show more…
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A bullet when fired at a target with velocity of $100 \mathrm{~ms}^{-1}$ penetrates $1 \mathrm{~m}$ into it. If the bullet is fired at a similar target with a thickness $0.5 \mathrm{~m}$, then it will emerge from it with a velocity of (a) $50 \sqrt{2} \mathrm{~m} / \mathrm{s}$ (b) $\frac{50}{\sqrt{2}} \mathrm{~m} / \mathrm{s}$ (c) $50 \mathrm{~m} / \mathrm{s}$ (d) $10 \mathrm{~m} / \mathrm{s}$
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Round 2
The velocity of a bullet is reduced from $200 \mathrm{~m} / \mathrm{s}$ to $100 \mathrm{~m} / \mathrm{s}$ while travelling through a wooden block of thickness 10cm. The retardation, assuming it to be uniform, will be (a) $10 \times 10^{4} \mathrm{~m} / \mathrm{s}^{2}$ (b) $12 \times 10^{4} \mathrm{~m} / \mathrm{s}^{2}$ (c) $13.5 \times 10^{4} \mathrm{~m} / \mathrm{s}^{2}$ (d) $15 \times 10^{4} \mathrm{~m} / \mathrm{s}^{2}$
The velocity of a bullet is reduced from 200m/s to 100m/s while travelling through a wooden block of thickness 10cm. The retardation, assuming it to be uniform, will be (a) 10 * 10^4 m/s^2 (b) 12 * 10^4 m/s^2 (c) 13.5 * 10^4 m/s^2 (d) 15 * 10^4 m/s^2
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