Question
Verify for $z=x+\mathrm{i} y \in \mathbb{C}$ the inequalities$$\frac{|x|+|y|}{\sqrt{2}} \leq|z|=\sqrt{x^{2}+y^{2}} \leq|x|+|y|$$and$$\max \{|x|,|y|\} \leq|z| \leq \sqrt{2} \max \{|x|,|y|\}$$
Step 1
The modulus of \( z \) is defined as \( |z| = \sqrt{x^2 + y^2} \). Step 2: To verify the first set of inequalities, we need to show both: Show more…
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